Match List-$I$ with List-$II$ and select the correct code:

List-$I$	List-$II$
$A$. Ziegler-Natta	$i$. $Fe_4[Fe(CN)_6]_3$
$B$. Brown ring complex	$ii$. $[Fe(H_2O)_5NO]SO_4$
$C$. Prussian Blue	$iii$. $Al(C_2H_5)_3 + TiCl_4$
$D$. Turnbull Blue	$iv$. $Fe_3[Fe(CN)_6]_2$

Correct code is:

The colour of $CuCr_2O_7$ solution in water is green because

The number of species having a square planar shape from the following is $........$.
$XeF_4$,$SF_4$,$SiF_4$,$BF_4^{-}$,$BrF_4^{-}$,$[Cu(NH_3)_4]^{2+}$,$[FeCl_4]^{2-}$,$[PtCl_4]^{2-}$

Match each coordination compound in List-$I$ with an appropriate pair of characteristics from List-$II$ and select the correct answer using the code given below the lists. $\{en = H_2NCH_2CH_2NH_2\}$,atomic numbers:$\{Ti = 22; Cr = 24; Co = 27; Pt = 78\}$

List-$I$	List-$II$
$P$. $[Cr(NH_3)_4Cl_2]Cl$	$1$. Paramagnetic and exhibits ionisation isomerism
$Q$. $[Ti(H_2O)_5Cl](NO_3)_2$	$2$. Diamagnetic and exhibits cis-trans isomerism
$R$. $[Pt(en)(NH_3)Cl]NO_3$	$3$. Paramagnetic and exhibits cis-trans isomerism
$S$. $[Co(NH_3)_4(NO_3)_2]NO_3$	$4$. Diamagnetic and exhibits ionisation isomerism

The aqueous solution of $CuCrO_4$ is green because it contains

The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $NiCl_2 \cdot 6H_2O$ to form a stable coordination compound. Assume that both the reactions are $100 \%$ complete. If $1584 \ g$ of ammonium sulphate and $952 \ g$ of $NiCl_2 \cdot 6H_2O$ are used in the preparation,the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is $\qquad$ (Atomic weights in $g \ mol^{-1}: H=1, N=14, O=16, S=32, Cl=35.5, Ca=40, Ni=59$)