Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Orbital)List-$II$ (Radial nodes and nodal plane)
$A$. $2s$$I$. $1$ Radial node + two nodal planes
$B$. $3s$$II$. $1$ Radial node + one nodal plane
$C$. $3p$$III$. $2$ Radial nodes + No nodal plane
$D$. $4d$$IV$. $1$ Radial node + No nodal plane

  • A
    $A-IV, B-I, C-III, D-II$
  • B
    $A-IV, B-II, C-III, D-I$
  • C
    $A-III, B-I, C-IV, D-II$
  • D
    $A-IV, B-III, C-II, D-I$

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Similar Questions

Match List-$I$ with List-$II$.
List-$I$ (Quantum Number) List-$II$ (Information provided)
$A$. $m_l$ $I$. Shape of orbital
$B$. $m_s$ $II$. Size of orbital
$C$. $l$ $III$. Orientation of orbital
$D$. $n$ $IV$. Orientation of spin of electron

Choose the correct answer from the options given below:

Which of the following orbitals is not possible (in $f$)?

In an atom,how many orbital$(s)$ will have the quantum numbers $n = 3, l = 2$ and $m_l = +2$?

In an atom,the total number of electrons having quantum numbers $n=4, |m_{l}|=1$ and $m_{s}=-\frac{1}{2}$ is:

Assertion :- In $H$-atom,the energy of $3d$-level is smaller than $4s$-level.
Reason :- In multi-electron species,an orbital with lower value of $(n+\ell)$ has energy smaller than the orbital with larger value of $(n+\ell)$.

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