Match the chemical reactions given in List-I | vedclass

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Question

(B) The reactions are classified as follows:$A$. $TiCl_{4(l)} + 2Mg_{(s)} \xrightarrow{\Delta} Ti_{(s)} + 2MgCl_{2(s)}$: Magnesium displaces Titanium,

Vedclass · Accepted Answer

$A-II, B-I, C-IV, D-III$

Vedclass · Answer

(B) The reactions are classified as follows:$A$. $TiCl_{4(l)} + 2Mg_{(s)} \xrightarrow{\Delta} Ti_{(s)} + 2MgCl_{2(s)}$: Magnesium displaces Titanium, hence it is a metal displacement reaction $(II)$.$B$. $2H_2O_{2(aq)} \rightarrow 2H_2O_{(l)} + O_{2(g)}$: Oxygen in $H_2O_2$ (oxidation state $-1$) goes to $-2$ in $H_2O$ and $0$ in $O_2$. This is a disproportionation reaction $(I)$.$C$. $C_{(s)} + O_{2(g)} \xrightarrow{\Delta} CO_{2(g)}$: Carbon and oxygen combine to form a single product, which is a combination reaction $(IV)$.$D$. $2NaH_{(s)} \xrightarrow{\Delta} 2Na_{(s)} + H_{2(g)}$: Sodium hydride breaks down into sodium and hydrogen, which is a decomposition reaction $(III)$.Therefore, the correct matching is $A-II, B-I, C-IV, D-III$.

List-$I$	List-$II$
$A$. $TiCl_{4(l)} + 2Mg_{(s)} \xrightarrow{\Delta} Ti_{(s)} + 2MgCl_{2(s)}$	$I$. Disproportionation reaction
$B$. $2H_2O_{2(aq)} \rightarrow 2H_2O_{(l)} + O_{2(g)}$	$II$. Metal displacement reaction
$C$. $C_{(s)} + O_{2(g)} \xrightarrow{\Delta} CO_{2(g)}$	$III$. Decomposition reaction
$D$. $2NaH_{(s)} \xrightarrow{\Delta} 2Na_{(s)} + H_{2(g)}$	$IV$. Combination reaction

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