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(B) The correct matches are as follows:$A$. Kohlrausch law states that the limiting molar conductivity of an electrolyte is the sum of the individual

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$A 	o (i), B 	o (ii), C 	o (iii), D 	o (iv)$

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(B) The correct matches are as follows:$A$. Kohlrausch law states that the limiting molar conductivity of an electrolyte is the sum of the individual contributions of the ions: $\Lambda _{m}^o = 
u _+ \lambda _+^o + 
u _- \lambda _-^o$. Thus,$A 	o (i)$.$B$. Molar conductivity is defined as $\Lambda _m = \frac{\kappa 	imes 1000}{M}$. Thus,$B 	o (ii)$.$C$. The degree of dissociation $\alpha$ is given by the ratio of molar conductivity at a given concentration to the limiting molar conductivity: $\alpha = \frac{\Lambda _m}{\Lambda _m^o}$. Thus,$C 	o (iii)$.$D$. The dissociation constant $K_a$ for a weak electrolyte is given by $K_a = \frac{C\alpha ^2}{1 - \alpha}$. Thus,$D 	o (iv)$.Therefore,the correct sequence is $A 	o (i), B 	o (ii), C 	o (iii), D 	o (iv)$.

Column $I$	Column $II$
$A$. Kohlrausch law	$i$. $\Lambda _{m}^o = \nu _+ \lambda _+^o + \nu _- \lambda _-^o$
$B$. Molar Conductivity	$ii$. $\Lambda _m = \frac{\kappa \times 1000}{M}$
$C$. Degree of Dissociation	$iii$. $\alpha = \frac{\Lambda _m}{\Lambda _m^o}$
$D$. Dissociation Constant	$iv$. $K_a = \frac{C\alpha ^2}{1 - \alpha}$

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