Match the following :- Column-I Colum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i)$ Adiabatic process is a process in which there is no transfer of heat between the system and the surroundings,i.e.,$dQ = 0$. Thus,$(i) \longr

Vedclass · Accepted Answer

$(i) \longrightarrow (d), (ii) \longrightarrow (b), (iii) \longrightarrow (a), (iv) \longrightarrow (c)$

Vedclass · Answer

(A) $(i)$ Adiabatic process is a process in which there is no transfer of heat between the system and the surroundings,i.e.,$dQ = 0$. Thus,$(i) \longrightarrow (d)$.$(ii)$ An isolated system is a system that cannot exchange either energy or matter with its surroundings. Thus,$(ii) \longrightarrow (b)$.$(iii)$ Isothermal change is a process that occurs at a constant temperature,i.e.,$dT = 0$. Thus,$(iii) \longrightarrow (a)$.$(iv)$ The law of conservation of energy is the fundamental principle behind the first law of thermodynamics,which states that energy can neither be created nor destroyed,only transformed. Thus,$(iv) \longrightarrow (c)$.Therefore,the correct matching is $(i) \longrightarrow (d), (ii) \longrightarrow (b), (iii) \longrightarrow (a), (iv) \longrightarrow (c)$.

Column-$I$	Column-$II$
$(i)$ Adiabatic process	$(a)$ Constant temperature
$(ii)$ Isolated system	$(b)$ No exchange of energy and matter
$(iii)$ Isothermal change	$(c)$ First law of thermodynamics
$(iv)$ Law of conservation of energy	$(d)$ No transfer of heat only

Match the following $:-$

Column-$I$ Column-$II$

$(i)$ Adiabatic process $(a)$ Constant temperature

$(ii)$ Isolated system $(b)$ No exchange of energy and matter

$(iii)$ Isothermal change $(c)$ First law of thermodynamics

$(iv)$ Law of conservation of energy $(d)$ No transfer of heat only

Similar Questions

The graph for $y = 1 - e^{-x}$ is represented by (for $x > 0$):

An ideal monoatomic gas is carried around the cycle $ABCDA$ as shown in the figure. The efficiency of the gas cycle is

An ideal gas expands isothermally from volume $V_1$ to volume $V_2$. It is then compressed to the original volume $V_1$ adiabatically. If $p_1$ and $p_2$ represent the initial pressure and final pressure respectively, and $W$ represents the net work done by the gas during the entire process, then:

One mole of an ideal gas having initial volume $V$,pressure $2P$ and temperature $T$ undergoes a cyclic process $ABCDA$ as shown below. The net work done in the complete cycle is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following $:-$ Column-$I$ Column-$II$ $(i)$ Adiabatic process $(a)$ Constant temperature $(ii)$ Isolated system $(b)$ No exchange of energy and matter $(iii)$ Isothermal change $(c)$ First law of thermodynamics $(iv)$ Law of conservation of energy $(d)$ No transfer of heat only