Match the following Column-$I$ (Reaction) with Column-$II$ (colour of the product or nature):
Column-$I$ (Reaction) Column-$II$ (colour of the product or nature) $(A)$ $FeCl_3(aq) + NH_3(aq) \rightarrow$ $(I)$ Green ppt $(B)$ $AgCl(aq) + NH_3(aq) \rightarrow$ $(II)$ Deep blue $(III)$ Brown ppt $(IV)$ Colourless solution
The correct answer for the sequence $(A, B)$ is:
| Column-$I$ (Reaction) | Column-$II$ (colour of the product or nature) |
| $(A)$ $FeCl_3(aq) + NH_3(aq) \rightarrow$ | $(I)$ Green ppt |
| $(B)$ $AgCl(aq) + NH_3(aq) \rightarrow$ | $(II)$ Deep blue |
| $(III)$ Brown ppt | |
| $(IV)$ Colourless solution |
The correct answer for the sequence $(A, B)$ is:
- A$I, II$
- B$I, III$
- C$III, IV$
- D$III, I$
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$CuSO_{4(aq)} + 4NH_3 \rightarrow X,$ then $X$ is
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$(a) \ Na_2[Fe(CN)_5NO]$
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$(c) \ K_4[Fe(CN)_6]$
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In the light of the above statements,choose the most appropriate answer from the options given below:
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Then final products $N$ and $O$ are respectively.
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