Match the items in Column-$I$ with the relevant item in Column-$II$.
Column-$I$ Column-$II$ $A$. Hydrogen peroxide is used as a $1$. zeolite $B$. Used in Calgon method $2$. perhydrol $C$. Permanent hardness of hard water is removed by $3$. sodium hexametaphosphate $4$. propellant
| Column-$I$ | Column-$II$ |
| $A$. Hydrogen peroxide is used as a | $1$. zeolite |
| $B$. Used in Calgon method | $2$. perhydrol |
| $C$. Permanent hardness of hard water is removed by | $3$. sodium hexametaphosphate |
| $4$. propellant |
(A-2,4; B-3; C-1,3) $A-2, 4; B-3; C-1, 3$.
$A$. Hydrogen peroxide $(H_2O_2)$ is known as perhydrol (at high concentrations) and is also used as a rocket propellant.
$B$. Calgon method uses sodium hexametaphosphate $(Na_6P_6O_{18})$ to remove hardness.
$C$. Permanent hardness of water is removed by using zeolites (ion exchange method) or sodium hexametaphosphate (Calgon method).
$A$. Hydrogen peroxide $(H_2O_2)$ is known as perhydrol (at high concentrations) and is also used as a rocket propellant.
$B$. Calgon method uses sodium hexametaphosphate $(Na_6P_6O_{18})$ to remove hardness.
$C$. Permanent hardness of water is removed by using zeolites (ion exchange method) or sodium hexametaphosphate (Calgon method).
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Similar Questions
Match Column-$I$ with Column-$II$ for the given properties/applications mentioned therein.
Column-$I$ Column-$II$ $A$. $H$ $1$. Used in the name of perhydrol. $B$. $H_2$ $2$. Can be reduced to dihydrogen by $NaH$. $C$. $H_2O$ $3$. Can be used in hydroformylation of olefin. $D$. $H_2O_2$ $4$. Can be used in cutting and welding.
| Column-$I$ | Column-$II$ |
| $A$. $H$ | $1$. Used in the name of perhydrol. |
| $B$. $H_2$ | $2$. Can be reduced to dihydrogen by $NaH$. |
| $C$. $H_2O$ | $3$. Can be used in hydroformylation of olefin. |
| $D$. $H_2O_2$ | $4$. Can be used in cutting and welding. |
Medium
View Solution$CuSO_4$ solution $+$ lime is called
Medium
View SolutionMatch the correct option from Column $-A$ and Column $-B$.
Column $-A$ Column $-B$ $(1).$ Calgon $(a).$ $D_2O$ $(2).$ Perhydrol $(b).$ Zeolite $(3).$ Heavy water $(c).$ Sodium hexametaphosphate $(4).$ Aluminosilicate $(d).$ Commercial name of Hydrogen peroxide
| Column $-A$ | Column $-B$ |
| $(1).$ Calgon | $(a).$ $D_2O$ |
| $(2).$ Perhydrol | $(b).$ Zeolite |
| $(3).$ Heavy water | $(c).$ Sodium hexametaphosphate |
| $(4).$ Aluminosilicate | $(d).$ Commercial name of Hydrogen peroxide |
Medium
View SolutionMatch the terms in Column $-I$ with the relevant item in Column $-II$.
Column $-I$ Column $-II$ $A$. Electrolysis of water produces $1$. atomic reactor $B$. Lithium aluminium hydride is used as $2$. polar molecule $C$. Hydrogen chloride is a $3$. recombines on metal surface to generate high temperature $D$. Heavy water is used in $4$. reducing agent $E$. Atomic hydrogen $5$. hydrogen and oxygen
| Column $-I$ | Column $-II$ |
| $A$. Electrolysis of water produces | $1$. atomic reactor |
| $B$. Lithium aluminium hydride is used as | $2$. polar molecule |
| $C$. Hydrogen chloride is a | $3$. recombines on metal surface to generate high temperature |
| $D$. Heavy water is used in | $4$. reducing agent |
| $E$. Atomic hydrogen | $5$. hydrogen and oxygen |
Difficult
View SolutionIn which of the following reactions,hydrogen is liberated?
$(i)$ $Al_{(s)} + HCl_{(aq)} \rightarrow$
$(ii)$ $Al_{(s)} + NaOH_{(aq)} \rightarrow$
$(iii)$ $NaBH_4 + I_2 \rightarrow$
$(i)$ $Al_{(s)} + HCl_{(aq)} \rightarrow$
$(ii)$ $Al_{(s)} + NaOH_{(aq)} \rightarrow$
$(iii)$ $NaBH_4 + I_2 \rightarrow$
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