Match the List-$I$ with List-$II$:
List-$I$ List-$II$ $A$. Finkelstein reaction $I$. $SbF_3$ $B$. Swarts reaction $II$. $Na$, dry ether $C$. Sandmeyer's reaction $III$. $NaI$ $D$. Fittig reaction $IV$. $Cu_2Cl_2$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $A$. Finkelstein reaction | $I$. $SbF_3$ |
| $B$. Swarts reaction | $II$. $Na$, dry ether |
| $C$. Sandmeyer's reaction | $III$. $NaI$ |
| $D$. Fittig reaction | $IV$. $Cu_2Cl_2$ |
Choose the correct answer from the options given below:
- A$A-I, B-IV, C-III, D-II$
- B$A-III, B-I, C-IV, D-II$
- C$A-IV, B-II, C-I, D-III$
- D$A-I, B-III, C-II, D-IV$
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Similar Questions
Provide the chemical reactions for the following conversions:
$1$. $2$-bromopropane and $1$-bromopropane from propene.
$2$. $2$-bromopropane from $1$-bromopropane.
$1$. $2$-bromopropane and $1$-bromopropane from propene.
$2$. $2$-bromopropane from $1$-bromopropane.
Difficult
View SolutionDraw the structures of major monohalo products in each of the following reactions:
Easy
View SolutionMatch the following reactions in List-$I$ with their major products in List-$II$.
List-$I$ (Reaction)
List-$II$ (Major product)
$A. \ CH_3CH=CH_2 \xrightarrow{HI}$
$I. \ 1\text{-bromo-}2\text{-phenylethane}$
$B. \ C_6H_5CH_2CH_3 \xrightarrow{Br_2/\Delta}$
$II. \ 1\text{-iodopropane}$
$C. \ C_6H_5CH=CH_2 \xrightarrow{HBr}$
$III. \ 2\text{-iodopropane}$
$IV. \ 1\text{-bromo-}1\text{-phenylethane}$
The correct match is:
| List-$I$ (Reaction) | List-$II$ (Major product) |
|---|---|
| $A. \ CH_3CH=CH_2 \xrightarrow{HI}$ | $I. \ 1\text{-bromo-}2\text{-phenylethane}$ |
| $B. \ C_6H_5CH_2CH_3 \xrightarrow{Br_2/\Delta}$ | $II. \ 1\text{-iodopropane}$ |
| $C. \ C_6H_5CH=CH_2 \xrightarrow{HBr}$ | $III. \ 2\text{-iodopropane}$ |
| $IV. \ 1\text{-bromo-}1\text{-phenylethane}$ |
The correct match is:
DifficultTS EAMCET 2021
View SolutionMatch the reactants in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Products) $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ $i$. $CH_3CH_2CH_2Br$ $B$. $CH_3CH=CH_2 + HI \rightarrow$ $ii$. $BrCH_2-CH_2Br$ $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ $iii$. $CH_3CHICH_3$ $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ $iv$. $C_6H_5I$
| Column-$I$ (Reactants) | Column-$II$ (Products) |
| $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ | $i$. $CH_3CH_2CH_2Br$ |
| $B$. $CH_3CH=CH_2 + HI \rightarrow$ | $ii$. $BrCH_2-CH_2Br$ |
| $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ | $iii$. $CH_3CHICH_3$ |
| $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ | $iv$. $C_6H_5I$ |
Medium
View Solution$C_3H_7I$ $(P)$ $\xrightarrow[\text{alc. } KOH]{\Delta}$ $Q$ $\xrightarrow{NBS}$ $R$ $\xrightarrow{KCN}$ $CH_2 = CH - CH_2 - CN$. $P$ can be:
Medium
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