The maximum usable frequency (MUF) in the F-r | vedclass

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(C) The formula for the maximum usable frequency $(MUF)$ is given by $MUF = \frac{f_c}{\cos 	heta}$,where $f_c$ is the critical frequency and $	heta

Vedclass · Accepted Answer

$175$

Vedclass · Answer

(C) The formula for the maximum usable frequency $(MUF)$ is given by $MUF = \frac{f_c}{\cos 	heta}$,where $f_c$ is the critical frequency and $	heta$ is the angle of incidence.Given: $f_c = 60 \, MHz$ and $	heta = 70^\circ$.Substituting the values: $MUF = \frac{60}{\cos 70^\circ}$.Since $\cos 70^\circ \approx 0.342$,we have $MUF = \frac{60}{0.342} \approx 175.43 \, MHz$.Rounding to the nearest integer,we get $x = 175 \, MHz$.

The maximum usable frequency $(MUF)$ in the $F$-region layer is $x$,when the critical frequency is $60 \, MHz$ and the angle of incidence is $70^\circ$. Then $x$ is ....... $MHz$.

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