Metal-metal bonding is more frequent in 4d or | vedclass

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(B) In the $d$-block elements,metal-metal bonding is more extensive in the $4d$ and $5d$ series compared to the $3d$ series. This is primarily because

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the large size of the orbitals which participates in the metal-metal bond formation

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(B) In the $d$-block elements,metal-metal bonding is more extensive in the $4d$ and $5d$ series compared to the $3d$ series. This is primarily because the $4d$ and $5d$ orbitals are larger in size and more diffuse than the $3d$ orbitals. Due to their larger size,these orbitals can effectively overlap with each other to form stronger metal-metal bonds. Therefore,the correct reason is the large size of the orbitals which participate in the metal-metal bond formation.

List-$I$	List-$II$
$(1)$ $Ti^+$	$(A)$ $(n-1)d^4ns^2$
$(2)$ $_{30}Zn$	$(B)$ $(n-1)d^{10}ns^1$
$(3)$ $_{24}Cr$	$(C)$ $(n-1)d^2ns^0$
$(4)$ $_{29}Cu$	$(D)$ $(n-1)d^5ns^1$
	$(E)$ $(n-1)d^0ns^2$
	$(F)$ $(n-1)d^{10}ns^2$

Metal-metal bonding is more frequent in $4d$ or $5d$ series than in $3d$ series due to

Similar Questions

Match the elements in List-$I$ with their electronic configurations in List-$II$.

List-$I$ List-$II$

$(1)$ $Ti^+$ $(A)$ $(n-1)d^4ns^2$

$(2)$ $_{30}Zn$ $(B)$ $(n-1)d^{10}ns^1$

$(3)$ $_{24}Cr$ $(C)$ $(n-1)d^2ns^0$

$(4)$ $_{29}Cu$ $(D)$ $(n-1)d^5ns^1$

$(E)$ $(n-1)d^0ns^2$

$(F)$ $(n-1)d^{10}ns^2$

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