Methyl-tert-butyl ether on heating with HI of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of ethers with $HI$ depends on the stability of the carbocation formed.In the case of methyl-tert-butyl ether,the protonation of the

Vedclass · Accepted Answer

$CH_3OH + (CH_3)_3CI$

Vedclass · Answer

(B) The reaction of ethers with $HI$ depends on the stability of the carbocation formed.In the case of methyl-tert-butyl ether,the protonation of the oxygen atom occurs first.$(CH_3)_3C-O-CH_3 + HI 	o (CH_3)_3C-O^+(H)-CH_3 + I^-$.Since the tert-butyl group can form a stable $3^{\circ}$ carbocation,the $I^-$ ion attacks the tert-butyl group via an $S_N1$ mechanism,leading to the formation of tert-butyl iodide and methanol.$(CH_3)_3C-O^+(H)-CH_3 	o (CH_3)_3C^+ + CH_3OH$.$(CH_3)_3C^+ + I^- 	o (CH_3)_3CI$.Thus,the products are $(CH_3)_3CI$ and $CH_3OH$.

Methyl-tert-butyl ether on heating with $HI$ of one molar concentration gives

Similar Questions

Ether on heating at high temperature in the presence of air forms an explosive compound. The structure of this compound is:

Diethyl ether and methyl $n$-propyl ether are:

The products formed in the following reaction are $C_6H_5-OCH_3 + HI \xrightarrow{\text{heat}}$

What are the products formed when phenyl ethyl ether is heated with concentrated $HBr$?

In the given reaction
$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$
$[X]$ and $[Y]$ will respectively be

Vedclass Test Series

Exam Paper Generator

Online Exam Module