Molar conductivities $\left(\Lambda_{m}^{\circ}\right)$ at infinite dilution of $NaCl$,$HCl$,and $CH_{3}COONa$ are $126.4$,$425.9$,and $91.0 \ S \ cm^{2} \ mol^{-1}$ respectively. $\Lambda_{m}^{\circ}$ for $CH_{3}COOH$ will be $:-$
- A$290.8 \ S \ cm^{2} \ mol^{-1}$
- B$390.5 \ S \ cm^{2} \ mol^{-1}$
- C$425.5 \ S \ cm^{2} \ mol^{-1}$
- D$180.5 \ S \ cm^{2} \ mol^{-1}$
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The molar conductances of $NaCl$,$HCl$,and $CH_3COONa$ at infinite dilution are $126.45$,$426.16$,and $91 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively. The molar conductance of $CH_3COOH$ at infinite dilution is .............. $\Omega^{-1} \ cm^2 \ mol^{-1}$.
MediumAIPMT 1997
View SolutionGiven below is the plot of the molar conductivity vs $\sqrt{concentration}$ for $KCl$ in aqueous solution. If,for the higher concentration of $KCl$ solution,the resistance of the conductivity cell is $100 \ \Omega$,then the resistance of the same cell with the dilute solution is '$x$' $\Omega$. The value of $x$ is $............$ ($Nearest$ $integer$)
DifficultJEE MAIN 2025
View SolutionThe electrical resistance of a column of $0.05 \ mol \ L^{-1}$ $NaOH$ solution of diameter $1 \ cm$ and length $50 \ cm$ is $5.55 \times 10^{3} \ \Omega$. Calculate its resistivity,conductivity and molar conductivity.
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