Molar ionic conductivities of a divalent cati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity of an electrolyte at infinite dilution is the sum of the mol

Vedclass · Accepted Answer

$130 \ S \ cm^2 \ mol^{-1}$

Vedclass · Answer

(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity of an electrolyte at infinite dilution is the sum of the molar ionic conductivities of its constituent ions.For an electrolyte $CA$ where $C$ is a divalent cation $(C^{2+})$ and $A$ is a divalent anion $(A^{2-})$,the molar conductivity is given by:$\Lambda_m^\circ = \lambda_+ + \lambda_-$Given:$\lambda_{C^{2+}} = 57 \ S \ cm^2 \ mol^{-1}$$\lambda_{A^{2-}} = 73 \ S \ cm^2 \ mol^{-1}$Therefore:$\Lambda_m^\circ = 57 + 73 = 130 \ S \ cm^2 \ mol^{-1}$

Molar ionic conductivities of a divalent cation and a divalent anion are $57 \ S \ cm^2 \ mol^{-1}$ and $73 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of a solution of an electrolyte containing these ions will be:

Similar Questions

The unit of equivalent conductivity is

The electronic conductance depends on

Which of the following graphs represents the variation of molar conductance $(\Lambda_m)$ of an electrolyte with $\sqrt{C}$ for weak and strong electrolytes,respectively?

If the conductivity of a $0.5 \ M \ KCl$ solution at $298 \ K$ is $0.024 \ S \ cm^{-1}$,then the molar conductivity of the solution would be $S \ cm^2 \ mol^{-1}$.

Write a note on the difficulties associated with the measurement of resistivity of an ionic solution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module