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(B) Let the amount invested in the first scheme be $Rs. x$ and in the second scheme be $Rs. (10500 - x)$.The rate of interest is $10 \% \, p.a.$ compo

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$5000$

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(B) Let the amount invested in the first scheme be $Rs. x$ and in the second scheme be $Rs. (10500 - x)$.The rate of interest is $10 \% \, p.a.$ compounded annually.The amount after $n$ years is given by $A = P(1 + r/100)^n$.For the first scheme,the amount after $2 \, years$ is $A_1 = x(1 + 10/100)^2 = x(1.1)^2 = 1.21x$.For the second scheme,the amount after $3 \, years$ is $A_2 = (10500 - x)(1 + 10/100)^3 = (10500 - x)(1.1)^3 = 1.331(10500 - x)$.Since the amounts are equal,$1.21x = 1.331(10500 - x)$.$1.21x = 13975.5 - 1.331x$.$1.21x + 1.331x = 13975.5$.$2.541x = 13975.5$.$x = 13975.5 / 2.541 = 5500$.The amount deposited for $3 \, years$ is $(10500 - x) = 10500 - 5500 = Rs. 5000$.

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