Calculate the total number of sigma bonds in | vedclass

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Question

(B) The structure of toluene $(C_6H_5CH_3)$ consists of a benzene ring attached to a methyl group $(-CH_3)$.In the benzene ring $(C_6H_6)$,there are $

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) The structure of toluene $(C_6H_5CH_3)$ consists of a benzene ring attached to a methyl group $(-CH_3)$.In the benzene ring $(C_6H_6)$,there are $6$ $C-C$ $\sigma$ bonds and $6$ $C-H$ $\sigma$ bonds. However,in toluene,one $H$ atom of the benzene ring is replaced by a $-CH_3$ group.Thus,the benzene ring part has $6$ $C-C$ $\sigma$ bonds and $5$ $C-H$ $\sigma$ bonds.The methyl group $(-CH_3)$ has $3$ $C-H$ $\sigma$ bonds and $1$ $C-C$ $\sigma$ bond (connecting the methyl group to the ring).Total $\sigma$ bonds = ($6$ $C-C$ ring bonds) + ($5$ $C-H$ ring bonds) + ($3$ $C-H$ methyl bonds) + ($1$ $C-C$ bond between ring and methyl) = $6 + 5 + 3 + 1 = 15$ $\sigma$ bonds.Therefore,the correct option is $(B)$.

Calculate the total number of $\sigma$ bonds in toluene $(C_6H_5CH_3)$.

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