The number of structural isomers of {C_4}{H_{ | vedclass

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(C) ${C_4}{H_{10}}O$ has $7$ structural isomers,consisting of $4$ alcohols and $3$ ethers.Alcohols:$1. 	ext{ } CH_3-CH_2-CH_2-CH_2-OH 	ext{ } (n-	e

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$7$

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(C) ${C_4}{H_{10}}O$ has $7$ structural isomers,consisting of $4$ alcohols and $3$ ethers.Alcohols:$1. 	ext{ } CH_3-CH_2-CH_2-CH_2-OH 	ext{ } (n-	ext{butyl alcohol})$$2. 	ext{ } CH_3-CH_2-CH(OH)-CH_3 	ext{ } (	ext{sec-butyl alcohol})$$3. 	ext{ } (CH_3)_2CH-CH_2-OH 	ext{ } (	ext{isobutyl alcohol})$$4. 	ext{ } (CH_3)_3C-OH 	ext{ } (	ext{tert-butyl alcohol})$Ethers:$5. 	ext{ } CH_3-CH_2-O-CH_2-CH_3 	ext{ } (	ext{diethyl ether})$$6. 	ext{ } CH_3-O-CH_2-CH_2-CH_3 	ext{ } (	ext{methyl propyl ether})$$7. 	ext{ } CH_3-O-CH(CH_3)_2 	ext{ } (	ext{methyl isopropyl ether})$

The number of structural isomers of ${C_4}{H_{10}}O$ is:

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