Observe the following four solutions :P : 10 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) buffer solution is a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid.$P$: $10 \ mL, 0.1 \ M \ NaOH$ (strong ba

Vedclass · Accepted Answer

$Q$,$R$,$S$ only

Vedclass · Answer

(D) buffer solution is a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid.$P$: $10 \ mL, 0.1 \ M \ NaOH$ (strong base) + $5 \ mL, 0.1 \ M \ HCl$ (strong acid). This results in a solution of $NaCl$ and excess $NaOH$. It is not a buffer.$Q$: $10 \ mL, 0.1 \ M \ NaOH$ + $15 \ mL, 0.1 \ M \ CH_3COOH$. $NaOH$ reacts with $CH_3COOH$ to form $CH_3COONa$ (conjugate base) and remaining $CH_3COOH$ (weak acid). This is an acidic buffer.$R$: $10 \ mL, 0.1 \ M \ NH_3$ (weak base) + $10 \ mL, 0.1 \ M \ NH_4Cl$ (conjugate acid). This is a basic buffer.$S$: $10 \ mL, 0.05 \ M \ NaF$ (conjugate base) + $5 \ mL, 0.1 \ M \ HF$ (weak acid). This is an acidic buffer.Therefore,$Q$,$R$,and $S$ act as buffers.

Similar Questions

$A$ buffer solution contains $0.1 \ mol$ of sodium acetate dissolved in $1000 \ cm^{3}$ of $0.1 \ M$ acetic acid. To the above buffer solution,$0.1 \ mol$ of sodium acetate is further added and dissolved. The $pH$ of the resulting buffer is

The principal buffer present in human blood is:

$pH$ of a mixture of $1 \ M$ benzoic acid $(pK_a = 4.20)$ and $1 \ M$ $C_6H_5COONa$ is $4.5$. What is the volume of benzoic acid required to prepare a $300 \ mL$ buffer solution (in $mL$)? $[\log 2 = 0.3]$

$A$ weak acid with a dissociation constant of $10^{-5}$ is being titrated with an aqueous $NaOH$ solution. The $pH$ at the point of one-third neutralization of the acid will be:

Which of the following is not an acidic buffer?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Observe the following four solutions :$P : 10 \ mL, 0.1 \ M \ NaOH + 5 \ mL, 0.1 \ M \ HCl$$Q : 10 \ mL, 0.1 \ M \ NaOH + 15 \ mL, 0.1 \ M \ CH_3COOH$$R : 10 \ mL, 0.1 \ M \ NH_3 + 10 \ mL, 0.1 \ M \ NH_4Cl$$S : 10 \ mL, 0.05 \ M \ NaF + 5 \ mL, 0.1 \ M \ HF$Which of above solutions act as buffer?