On combustion,0.210 g of an organic compound | vedclass

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(B) In the combustion of an organic compound,all $C$ in $CO_2$ and all $H$ in $H_2O$ comes from the organic compound.Mass of $C$ in $CO_2 = \frac{12}{

Vedclass · Accepted Answer

$6.72, 53.41$

Vedclass · Answer

(B) In the combustion of an organic compound,all $C$ in $CO_2$ and all $H$ in $H_2O$ comes from the organic compound.Mass of $C$ in $CO_2 = \frac{12}{44} 	imes 0.307 \ g = 0.0837 \ g$.Mass of $H$ in $H_2O = \frac{2}{18} 	imes 0.127 \ g = 0.0141 \ g$.Percentage of $H = \frac{0.0141}{0.210} 	imes 100 = 6.714 \% \approx 6.72 \%$.Mass of $O$ in the compound = Total mass - (Mass of $C$ + Mass of $H$) = $0.210 - (0.0837 + 0.0141) = 0.1122 \ g$.Percentage of $O = \frac{0.1122}{0.210} 	imes 100 = 53.428 \% \approx 53.41 \%$.Therefore,the percentages of $H$ and $O$ are $6.72 \%$ and $53.41 \%$ respectively.

On combustion,$0.210 \ g$ of an organic compound containing $C$,$H$,and $O$ gave $0.127 \ g$ $H_2O$ and $0.307 \ g$ $CO_2$. The percentages of hydrogen and oxygen in the given organic compound respectively are $:$

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