On plotting the points O(0,0), A(3,0), B(3,4) | vedclass

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(B) The coordinates of the vertices are $O(0,0), A(3,0), B(3,4)$,and $C(0,4)$.Calculating the lengths of the sides using the distance formula $d = \sq

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Rectangle

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(B) The coordinates of the vertices are $O(0,0), A(3,0), B(3,4)$,and $C(0,4)$.Calculating the lengths of the sides using the distance formula $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$:$OA = \sqrt{(3-0)^2 + (0-0)^2} = \sqrt{3^2} = 3$ units.$AB = \sqrt{(3-3)^2 + (4-0)^2} = \sqrt{4^2} = 4$ units.$BC = \sqrt{(0-3)^2 + (4-4)^2} = \sqrt{(-3)^2} = 3$ units.$CO = \sqrt{(0-0)^2 + (0-4)^2} = \sqrt{(-4)^2} = 4$ units.Since opposite sides are equal ($OA = BC = 3$ units and $AB = CO = 4$ units) and the adjacent sides are perpendicular (as they lie along the axes),the figure $OABC$ is a rectangle.

On plotting the points $O(0,0), A(3,0), B(3,4)$,and $C(0,4)$ and joining $OA, AB, BC$,and $CO$,which of the following figures is obtained?

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