One $year$ ago,a father was four times as old as his son. In $6$ $years$ time,his age will exceed twice his son's age by $9$ $years$. The ratio of their present ages is:

$A$ father's age is three times the sum of the ages of his two children,but $20 \, \text{years}$ hence his age will be equal to the sum of their ages. Then,the father's age is (in $\text{years}$)

$3 \text{ years}$ ago,the average age of a family of $5$ members was $17 \text{ years}$. $A$ baby having been born,the average age of the family is the same today. What is the age of the child? (in $\text{years}$)

The ratio between the present ages of $P$ and $Q$ is $5: 7$. If the difference between $Q$'s present age and $P$'s age after $6$ $years$ is $2$,what is the sum of ages of $P$ and $Q$ at present? (in $years$)

Present ages of Sameer and Anand are in the ratio $5:4$. Three years hence,the ratio of their ages will become $11:9$. What is Anand's present age in years?

In a family,a couple has a son and a daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is $9$ years younger than her husband and the brother is $7$ years older than his sister. What is the age of the mother? (in years)