One end of a uniform rod of mass m_1 and cros | vedclass

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(C) The stress at any cross-section of the rod is defined as the force acting on that cross-section divided by the area $A$.Consider the rod of mass $

Vedclass · Accepted Answer

$\frac{g(2m_2 + m_1)}{2A}$

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(C) The stress at any cross-section of the rod is defined as the force acting on that cross-section divided by the area $A$.Consider the rod of mass $m_1$ and length $L$. The mass per unit length is $\lambda = \frac{m_1}{L}$.At the midpoint of the rod,the total force acting downwards is the sum of the mass $m_2$ and the mass of the lower half of the rod.The mass of the lower half of the rod is $m_{half} = \frac{m_1}{2}$.Therefore,the total force $F$ at the midpoint is:$F = (m_2 + \frac{m_1}{2})g$Stress is given by $	ext{Stress} = \frac{F}{A}$.Substituting the value of $F$:$	ext{Stress} = \frac{(m_2 + \frac{m_1}{2})g}{A} = \frac{(\frac{2m_2 + m_1}{2})g}{A} = \frac{g(2m_2 + m_1)}{2A}$.

One end of a uniform rod of mass $m_1$ and cross-sectional area $A$ is hung from a ceiling. The other end of the rod is supporting a mass $m_2$. The stress at the midpoint of the rod is:

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