One litre of oxygen at a pressure of 1, atm a | vedclass

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(C) The ideal gas equation is given by $PV = nRT$ $...(i)$For oxygen: $P_1 = 1\, atm$,$V_1 = 1\, L$. Using $(i)$,$n_{O_2} = \frac{P_1 V_1}{RT} = \frac

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(C) The ideal gas equation is given by $PV = nRT$ $...(i)$For oxygen: $P_1 = 1\, atm$,$V_1 = 1\, L$. Using $(i)$,$n_{O_2} = \frac{P_1 V_1}{RT} = \frac{1 	imes 1}{RT} = \frac{1}{RT}$.For nitrogen: $P_2 = 0.5\, atm$,$V_2 = 2\, L$. Using $(i)$,$n_{N_2} = \frac{P_2 V_2}{RT} = \frac{0.5 	imes 2}{RT} = \frac{1}{RT}$.For the mixture in a vessel of volume $V_{mix} = 1\, L$ at the same temperature $T$:$P_{mix} V_{mix} = n_{total} RT$$P_{mix} 	imes 1 = (n_{O_2} + n_{N_2}) RT$$P_{mix} = (\frac{1}{RT} + \frac{1}{RT}) RT$$P_{mix} = \frac{2}{RT} 	imes RT = 2\, atm$.

One litre of oxygen at a pressure of $1\, atm$ and two litres of nitrogen at a pressure of $0.5\, atm$ are introduced into a vessel of volume $1\, L$. If there is no change in temperature,the final pressure of the mixture of gas (in $atm$) is

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