One mole of H_{2}O means:(i) 18 text{ g} of H | vedclass

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(D) The molar mass of water $(H_{2}O)$ is calculated as: $(2 	imes 1) + 16 = 18 	ext{ g/mol}$.By definition,one mole of any substance contains $6.02

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Both $(i)$ and $(ii)$ are correct

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(D) The molar mass of water $(H_{2}O)$ is calculated as: $(2 	imes 1) + 16 = 18 	ext{ g/mol}$.By definition,one mole of any substance contains $6.022 	imes 10^{23}$ particles (Avogadro's number) and its mass is equal to its molar mass in grams.Therefore,$1 	ext{ mole}$ of $H_{2}O = 18 	ext{ g}$ of $H_{2}O$ and contains $6.022 	imes 10^{23}$ molecules of $H_{2}O$.Thus,statements $(i)$ and $(ii)$ are correct.

One mole of $H_{2}O$ means:
$(i)$ $18 \text{ g}$ of $H_{2}O$
$(ii)$ $6.022 \times 10^{23}$ molecules of $H_{2}O$
$(iii)$ $180 \text{ g}$ of $H_{2}O$
$(iv)$ $1.8 \text{ g}$ of $H_{2}O$

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One mole of $H_{2}O$ means:$(i)$ $18 \text{ g}$ of $H_{2}O$$(ii)$ $6.022 \times 10^{23}$ molecules of $H_{2}O$$(iii)$ $180 \text{ g}$ of $H_{2}O$$(iv)$ $1.8 \text{ g}$ of $H_{2}O$