Calculate the number of molecules in 90 grams | vedclass

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(C) $(i)$ The molar mass of water $(H_2O)$ is $(2 	imes 1) + 16 = 18 	ext{ g/mol}$.$(ii)$ Number of moles in $90 	ext{ g}$ of water $= \frac{	ext{

Vedclass · Accepted Answer

$3.011 	imes 10^{24}$

Vedclass · Answer

(C) $(i)$ The molar mass of water $(H_2O)$ is $(2 	imes 1) + 16 = 18 	ext{ g/mol}$.$(ii)$ Number of moles in $90 	ext{ g}$ of water $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{90}{18} = 5 	ext{ moles}$.$(iii)$ Number of molecules $=$ Number of moles $	imes$ Avogadro's number $(N_A)$.$= 5 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol}$.$= 3.011 	imes 10^{24} 	ext{ molecules}$.

Calculate the number of molecules in $90$ grams of water.

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