Which of the following will have maximum mass | vedclass

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(B) To find the maximum mass,we calculate the mass for each option:$1$. $10^{22}$ molecules of $H_2O$: Mass = $(10^{22} / 6.022 	imes 10^{23}) 	imes

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$2$ moles of $H_2O$

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(B) To find the maximum mass,we calculate the mass for each option:$1$. $10^{22}$ molecules of $H_2O$: Mass = $(10^{22} / 6.022 	imes 10^{23}) 	imes 18 \approx 0.0166 	imes 18 \approx 0.299 	ext{ g}$.$2$. $2$ moles of $H_2O$: Mass = $2 	imes 18 = 36 	ext{ g}$.$3$. $10^{22}$ molecules of $NH_3$: Mass = $(10^{22} / 6.022 	imes 10^{23}) 	imes 17 \approx 0.0166 	imes 17 \approx 0.282 	ext{ g}$.$4$. $2$ moles of $NH_3$: Mass = $2 	imes 17 = 34 	ext{ g}$.Comparing these values,$36 	ext{ g}$ is the maximum mass. Thus,$2$ moles of $H_2O$ has the maximum mass.

Which of the following will have maximum mass?

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