One mole of ammonia was completely absorbed i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reactions are: $(a)$ $NH_{3} + HCl \rightarrow NH_{4}Cl$ (Salt of strong acid and weak base,$pH < 7$). $(b)$ $NH_{3} + CH_{3}COOH \rightarrow

Vedclass · Accepted Answer

$b > a > c$

Vedclass · Answer

(D) The reactions are: $(a)$ $NH_{3} + HCl \rightarrow NH_{4}Cl$ (Salt of strong acid and weak base,$pH For $(a)$,$pH = 7 - \frac{1}{2}(pK_{b} + \log C) = 7 - \frac{1}{2}(4.74 + 0) = 4.63$. For $(b)$,$pH = 7 + \frac{1}{2}(pK_{a} - pK_{b}) = 7 + \frac{1}{2}(4.74 - 4.74) = 7.0$. For $(c)$,$H_{2}SO_{4}$ is a strong diprotic acid. $1 \ M \ H_{2}SO_{4}$ provides $2 \ M \ H^{+}$,which reacts with $1 \ M \ NH_{3}$ to leave $1 \ M \ H^{+}$ and $0.5 \ M \ (NH_{4})_{2}SO_{4}$. This results in a highly acidic solution $(pH Thus,the order of $pH$ is $b (7.0) > a (4.63) > c ( a > c$.

One mole of ammonia was completely absorbed in one litre solution each of $(a)$ $1 \ M \ HCl$,$(b)$ $1 \ M \ CH_{3}COOH$,and $(c)$ $1 \ M \ H_{2}SO_{4}$ at $298 \ K$. The decreasing order for the $pH$ of the resulting solutions is (Given $pK_{b}(NH_{3}) = 4.74$)

Similar Questions

$20 \ mL$ of $0.5 \ N \ HCl$ and $35 \ mL$ of $0.1 \ N \ NaOH$ are mixed. The resulting solution will

How much heat is evolved when $100 \, mL$ of $0.1 \, N \, H_2SO_4$ is mixed with $150 \, mL$ of $0.1 \, N \, NaOH$?

The ionization constant of $ClCH_{2}COOH$ is $1.35 \times 10^{-3}$. What will be the $pH$ of $0.1 \ M$ acid and its $0.1 \ M$ sodium salt solution?

Statement $A$: Addition of $NH_4OH$ in the presence of excess $NH_4Cl$ to an aqueous solution of $BaCl_2$ results in the precipitation of $Ba(OH)_2$.
Reason $B$: $Ba(OH)_2$ is insoluble in water.

At $25\, ^oC$,the dissociation constant of $CH_3COOH$ and $NH_4OH$ in aqueous solution are almost the same. The $pH$ of a $0.01\, N$ $CH_3COOH$ solution is $4.0$ at $25\, ^oC$. The $pH$ of a $0.01\, N$ $NH_4OH$ solution at the same temperature would be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module