One mole of phenol is treated with dilute HNO | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Phenol $(C_6H_5OH)$ reacts with dilute $HNO_3$ to form a mixture of $o$-nitrophenol and $p$-nitrophenol.$o$-Nitrophenol is steam volatile due to i

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(D) Phenol $(C_6H_5OH)$ reacts with dilute $HNO_3$ to form a mixture of $o$-nitrophenol and $p$-nitrophenol.$o$-Nitrophenol is steam volatile due to intramolecular hydrogen bonding, while $p$-nitrophenol is not due to intermolecular hydrogen bonding.Thus, the steam volatile compound $(X)$ is $o$-nitrophenol $(C_6H_5NO_3)$.Molar mass of phenol $(C_6H_6O)$ = $(6 	imes 12) + (6 	imes 1) + 16 = 94 \ g \ mol^{-1}$.Percentage of oxygen in phenol = $(16 / 94) 	imes 100 \approx 17.021 \ \%$.Molar mass of $o$-nitrophenol $(C_6H_5NO_3)$ = $(6 	imes 12) + (5 	imes 1) + 14 + (3 	imes 16) = 72 + 5 + 14 + 48 = 139 \ g \ mol^{-1}$.Percentage of oxygen in $o$-nitrophenol = $(48 / 139) 	imes 100 \approx 34.532 \ \%$.Increase in percentage of oxygen = $34.532 - 17.021 = 17.511 \ \%$.Expressing as $175.11 	imes 10^{-1} \% \approx 175 	imes 10^{-1} \%$. Given the options provided, the closest integer value is $175$ (Note: The provided options in the prompt seem to be placeholders; based on standard calculation, the result is $175$).

Similar Questions

Identify the product of the following reaction.

Which of the following compounds will react with an acid chloride to form an ester?

What amount of bromine will be required to convert $2 \ g$ of phenol into $2, 4, 6-$tribromophenol (in $g$)? $($Given molar mass in $g \ mol^{-1}$ of $C, H, O, Br$ are $12, 1, 16, 80$ respectively$)$

What are $X$ and $Y$ respectively in the following set of reactions?

What are $A, B, C$ and $D$ in the following reactions?
$i)$ Aniline $\xrightarrow[273 \ K]{NaNO_2 \mid HCl} A$ $\xrightarrow{B} \text{Phenol}$
$ii)$ Cumene $\xrightarrow{O_2} C$ $\xrightarrow{D} \text{Phenol} + \text{acetone}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module