One ticket is selected at random from $50$ tickets numbered $00, 01, 02, \ldots, 49$. The probability that the sum of the digits on the selected ticket is $8$,given that the product of these digits is zero,equals:

  • A
    $\frac{1}{50}$
  • B
    $\frac{14}{50}$
  • C
    $\frac{5}{14}$
  • D
    $\frac{1}{14}$

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