The orbital angular momentum for a d-electron | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The orbital angular momentum of an electron is given by the formula: $	ext{Angular Momentum} = \sqrt{l(l + 1)} \frac{h}{2\pi}$.For a $d$-electron

Vedclass · Accepted Answer

$\frac{\sqrt{6}h}{2\pi}$

Vedclass · Answer

(B) The orbital angular momentum of an electron is given by the formula: $	ext{Angular Momentum} = \sqrt{l(l + 1)} \frac{h}{2\pi}$.For a $d$-electron,the azimuthal quantum number $l = 2$.Substituting the value of $l$ into the formula:$	ext{Angular Momentum} = \sqrt{2(2 + 1)} \frac{h}{2\pi} = \sqrt{2(3)} \frac{h}{2\pi} = \sqrt{6} \frac{h}{2\pi}$.Thus,the correct option is $B$.

The orbital angular momentum for a $d$-electron is

Similar Questions

Which of the following sets of quantum numbers is not possible?

The electronic configuration of the element with atomic number $24$ is:

How many unpaired electrons are present in a carbon atom in its ground state?

Quantum numbers $l = 2$ and $m = 0$ represent which orbital?

The maximum number of electrons present in an orbital with $n=4, l=3$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module