The order of first ionization potentials of e | vedclass

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Question

(B) The first ionization potential $(IE_1)$ increases across a period from left to right and decreases down a group.For the given elements:$1$. $Li$ $

Vedclass · Accepted Answer

$Be > B > Li > Na$

Vedclass · Answer

(B) The first ionization potential $(IE_1)$ increases across a period from left to right and decreases down a group.For the given elements:$1$. $Li$ $(2s^1)$ and $Be$ $(2s^2)$ are in the $2^{nd}$ period.$2$. $B$ $(2s^2 2p^1)$ is also in the $2^{nd}$ period.$3$. $Na$ $(3s^1)$ is in the $3^{rd}$ period.Comparing $Li, Be, B$: $Be$ has a fully filled $2s$ orbital,making it more stable than $B$. Thus,$IE_1$ of $Be > B > Li$.Comparing with $Na$: $Na$ has the lowest $IE_1$ because it is in the $3^{rd}$ period.The correct order is $Be > B > Li > Na$.

The order of first ionization potentials of elements $Li, Be, B, Na$ is:

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