Out of CHCl_3,CH_4,and SF_4,the molecules tha | vedclass

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(B) molecule has a regular geometry if all bond angles are equal and all bond lengths are identical,which typically occurs when the central atom has n

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$CHCl_3$ and $SF_4$

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(B) molecule has a regular geometry if all bond angles are equal and all bond lengths are identical,which typically occurs when the central atom has no lone pairs and all surrounding atoms are the same.$CH_4$ has a tetrahedral geometry with $sp^3$ hybridization and no lone pairs,resulting in a regular geometry.$CHCl_3$ has different atoms ($H$ and $Cl$) attached to the central carbon atom,leading to unequal bond angles and bond lengths,thus it lacks regular geometry.$SF_4$ has $sp^3d$ hybridization with one lone pair on the sulfur atom,which causes distortion in the bond angles (seesaw shape),resulting in an irregular geometry.Therefore,$CHCl_3$ and $SF_4$ do not have regular geometry.

Out of $CHCl_3$,$CH_4$,and $SF_4$,the molecules that do not have regular geometry are

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