Out of 10 white,9 black and 7 red balls,the n | vedclass

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(C) The number of ways to select $0$ or more balls of a specific color is equal to the number of balls of that color plus $1$ (for the case of selecti

Vedclass · Accepted Answer

$879$

Vedclass · Answer

(C) The number of ways to select $0$ or more balls of a specific color is equal to the number of balls of that color plus $1$ (for the case of selecting none).For $10$ white balls,there are $(10 + 1) = 11$ ways.For $9$ black balls,there are $(9 + 1) = 10$ ways.For $7$ red balls,there are $(7 + 1) = 8$ ways.The total number of ways to select balls is $(11 	imes 10 	imes 8) = 880$.Since the question asks for the selection of one or more balls,we must exclude the case where no balls are selected (i.e.,$0$ balls of each color).Therefore,the required number of ways is $880 - 1 = 879$.

Out of $10$ white,$9$ black and $7$ red balls,the number of ways in which selection of one or more balls can be made,is

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