Out of the following outer electronic configu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The highest oxidation state is achieved by $(n-1) d^5 n s^2$, which corresponds to a maximum oxidation state of $+7$. This is because the $(n-1) d

Vedclass · Accepted Answer

$(n-1) d^5 n s^2$

Vedclass · Answer

(B) The highest oxidation state is achieved by $(n-1) d^5 n s^2$, which corresponds to a maximum oxidation state of $+7$. This is because the $(n-1) d$-electrons can participate in bonding along with $n s$-electrons, as their energy levels are comparable. The oxidation states for the given configurations are summarized below:| Electronic configuration | Oxidation state || :--- | :--- || $(n-1) d^8 n s^2$ | $+2, +3, +4$ || $(n-1) d^3 n s^2$ | $+2, +3, +4, +5$ || $(n-1) d^5 n s^1$ | $+2, +3, +4, +5, +6$ || $(n-1) d^5 n s^2$ | $+2, +3, +4, +5, +6, +7$ |

Out of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one?

Similar Questions

$E^o$ for the conversion of $Ce^{+4}$ into $Ce^{+3}$ is $1.74 \ V$. It suggests that

Which one of the following does not correctly represent the correct order of the property indicated against it?

Which of the following species is paramagnetic? $Fe^{2+}, Zn^0, Hg^{2+}, Ti^{4+}$

Which pair of ions have the same magnetic moment?

The set having ions which are coloured and paramagnetic both is :

Vedclass Test Series

Exam Paper Generator

Online Exam Module