Out of the following transitions in a hydroge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The frequency of an emitted photon during an electronic transition is given by the relation $E = h
u = E_i - E_f$,where $E_i$ is the initial ener

Vedclass · Accepted Answer

$n=2$ to $n=1$

Vedclass · Answer

(B) The frequency of an emitted photon during an electronic transition is given by the relation $E = h
u = E_i - E_f$,where $E_i$ is the initial energy level and $E_f$ is the final energy level.For emission to occur,the electron must transition from a higher energy level to a lower energy level $(n_i > n_f)$.Thus,options $A$ ($n=1$ to $n=2$) and $C$ ($n=2$ to $n=6$) involve absorption,not emission,and can be eliminated.Comparing the emission transitions:$1$. For $n=2$ to $n=1$: $\Delta E = 13.6 \left( \frac{1}{1^2} - \frac{1}{2^2} ight) = 13.6 	imes 0.75 = 10.2 	ext{ eV}$.$2$. For $n=6$ to $n=2$: $\Delta E = 13.6 \left( \frac{1}{2^2} - \frac{1}{6^2} ight) = 13.6 \left( 0.25 - 0.0277 ight) = 13.6 	imes 0.2223 \approx 3.02 	ext{ eV}$.Since frequency $
u = \frac{\Delta E}{h}$,the transition with the largest energy difference $\Delta E$ will emit the photon with the highest frequency.Therefore,the transition $n=2$ to $n=1$ emits the photon of the highest frequency.

Out of the following transitions in a hydrogen atom,identify the transition which emits photons of highest frequency.

Similar Questions

The energy levels for an electron in a certain atom are shown in the figure. Which of the following transitions will emit a photon with the highest energy?

The ionization potential of a hydrogen atom is $13.6 \text{ eV}$. How much energy needs to be supplied to ionize a hydrogen atom in the first excited state (in $\text{ eV}$)?

In a hydrogen atom,if the difference in the energy of the electron in $n = 2$ and $n = 3$ orbits is $E,$ the ionization energy of the hydrogen atom is ....... $E$.

The four lowest energy levels of an $H$-atom are shown in the figure. The number of possible emission lines would be

The minimum excitation energy of an electron revolving in the first orbit of hydrogen is (in $eV$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module