The oxidation number of C in HNC is: | vedclass

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(A) In $HNC$,the structure is $H-N \rightrightarrows C$. The bond between $N$ and $C$ consists of one covalent bond and one coordinate bond. The coord

Vedclass · Accepted Answer

$+2$

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(A) In $HNC$,the structure is $H-N ightrightarrows C$. The bond between $N$ and $C$ consists of one covalent bond and one coordinate bond. The coordinate bond is directed from $N$ to $C$. Assigning oxidation states: $H$ is $+1$. $N$ is more electronegative than $H$,so $N$ takes $-1$ from the $H-N$ bond. For the $N ightrightarrows C$ bond,the coordinate bond does not contribute to the oxidation state calculation in the standard convention where electrons are assigned to the more electronegative atom. Thus,$O.N. 	ext{ of } H = +1$,$O.N. 	ext{ of } N = -3$,and $O.N. 	ext{ of } C = +2$.

The oxidation number of $C$ in $HNC$ is:

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