(A) In the coordination compound $Ni(CO)_4$,the ligand is carbonyl $(CO)$,which is a neutral ligand with an oxidation state of $0$. Let the oxidation

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(A) In the coordination compound $Ni(CO)_4$,the ligand is carbonyl $(CO)$,which is a neutral ligand with an oxidation state of $0$. Let the oxidation state of $Ni$ be $x$. The sum of oxidation states of all atoms in a neutral complex is $0$. $x + 4 \times (0) = 0$ $x = 0$. Therefore,the oxidation number of nickel in $Ni(CO)_4$ is $0$.