Oxidation state of manganese in potassium per | vedclass

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Question

(B) The chemical formula for potassium permanganate is $KMnO_4$. Oxidation number of $K = +1$. Oxidation number of $O = -2$. Since $KMnO_4$ is a neutr

Vedclass · Accepted Answer

$+7$

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(B) The chemical formula for potassium permanganate is $KMnO_4$. Oxidation number of $K = +1$. Oxidation number of $O = -2$. Since $KMnO_4$ is a neutral molecule,the sum of the oxidation numbers of all atoms must be $0$. Let the oxidation number of $Mn$ be $x$. $(+1) + x + 4 	imes (-2) = 0$. $1 + x - 8 = 0$. $x - 7 = 0$. $	herefore x = +7$. Thus,the oxidation state of manganese in $KMnO_4$ is $+7$.

Oxidation state of manganese in potassium permanganate is:

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