The ozonolysis products of an olefin are $CHO-CHO$ and $CHO-CH_2-CH_2-CHO$. The olefin is:

Arrange $HI$,$HCl$,$HBr$,and $HF$ in increasing order of rate of reaction with alkene.

Electrolysis of cold concentrated aqueous solution of potassium succinate yields:

What is the major product formed when propene reacts with $ICl$?

An alkene $X$ with formula $C_4H_8$ does not exhibit geometrical isomerism. In the conversion of $X$ to $Y$,the correct sequence of reagents $A$ and $B$ used are ($Y$ gives iodoform test):
$X$ $\xrightarrow{A} \text{Intermediate}$ $\xrightarrow{B} Y$

Suppose the following reaction sequence: $CH \equiv CH$ $\xrightarrow[\text{excess}]{NaNH_2 / \text{liq. } NH_3} A$ $\xrightarrow{2 CH_3 - I} B$ $\xrightarrow{H_2 / Pd - BaSO_4, \text{ quinoline}} C$ and $C$ $\xrightarrow{H_2 / Pd - BaSO_4, \text{ quinoline}}$ $\xrightarrow{NaNH_2 / \text{liq. } NH_3} D$. How are $C$ and $D$ related?