(A) According to Einstein's photoelectric equation, the maximum kinetic energy $K_{max}$ of the emitted photoelectron is given by:$K_{max} = h\nu - \p

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(A) According to Einstein's photoelectric equation, the maximum kinetic energy $K_{max}$ of the emitted photoelectron is given by:$K_{max} = h\nu - \phi$where $\phi$ is the work function of the metal.Given that the threshold frequency is $\nu$, the work function is $\phi = h\nu$.When radiation of frequency $2\nu$ is incident on the metal, the maximum kinetic energy is:$K_{max} = h(2\nu) - h\nu = h\nu$Since $K_{max} = \frac{1}{2}mv_{max}^2$, we have:$\frac{1}{2}mv_{max}^2 = h\nu$$v_{max}^2 = \frac{2h\nu}{m}$$v_{max} = \sqrt{\frac{2h\nu}{m}}$Therefore, option $A$ is correct.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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Photoelectric emission takes place from a certain metal at threshold frequency $\nu$. If the radiation of frequency $2\nu$ is incident on the metal plate, the maximum velocity of the emitted photoelectron will be ($m = \text{mass of electron}$, $h = \text{Planck's constant}$)

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A
$\sqrt{\frac{2h\nu}{m}}$
B
$\sqrt{\frac{h\nu}{2m}}$
C
$\sqrt{\frac{h\nu}{3m}}$
D
$\sqrt{\frac{h\nu}{m}}$

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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When radiation of wavelength $\lambda$ is incident on a metal,the stopping potential of photoelectrons is $4.8 \ V$. When radiation of wavelength $2\lambda$ is incident on the same metal,the stopping potential is $1.6 \ V$. What is the threshold wavelength of the metal?

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Photoelectric emission takes place from a certain metal at threshold frequency $\nu$. If the radiation of frequency $2\nu$ is incident on the metal plate, the maximum velocity of the emitted photoelectron will be ($m = \text{mass of electron}$, $h = \text{Planck's constant}$)

Similar Questions

When radiation of wavelength $\lambda$ is incident on a metal,the stopping potential of photoelectrons is $4.8 \ V$. When radiation of wavelength $2\lambda$ is incident on the same metal,the stopping potential is $1.6 \ V$. What is the threshold wavelength of the metal?

When photons of energy $1 \ eV$ and $2.5 \ eV$ are incident on a metal surface with a work function of $0.5 \ eV$,what is the ratio of the maximum kinetic energies of the emitted photoelectrons?

Light of wavelength $4000 \ \mathring A$ is incident on a photosensitive surface. If a potential of $-2 \ V$ is required to stop the emitted electrons,the work function of the material is: $(h = 6.6 \times 10^{-34} \ J \cdot s, e = 1.6 \times 10^{-19} \ C, c = 3 \times 10^8 \ m/s)$ (in $eV$)

What is the threshold wavelength in $nm$ for a metal with a work function of $4.0 \ eV$?

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