The plate voltage of a triode is increased from $200 \, V$ to $225 \, V$. To maintain the plate current,a change in grid voltage from $5 \, V$ to $5.75 \, V$ is required. The amplification factor is:

The grid voltage of any triode valve is changed from $-1 \, V$ to $-3 \, V$ and the mutual conductance is $3 \times 10^{-4} \, \text{mho}$. The change in plate circuit current will be ..... $mA$.

For a triode, ${r_p} = 10 \text{ k}\Omega$ and ${g_m} = 3 \text{ m}\mho$. If the load resistance is double the plate resistance, then the value of the voltage gain will be:

The slope of the anode characteristic and the mutual characteristic of a triode are $0.02 \text{ mA/V}$ and $1 \text{ mA/V}$ respectively. The amplification factor of the valve is:

In the circuit of a triode valve,there is no change in the plate current when the plate potential is increased from $200 \ V$ to $220 \ V$ and the grid potential is decreased from $-0.5 \ V$ to $-1.3 \ V$. The amplification factor of this valve is

In the grid circuit of a triode,a signal $E = 2\sqrt{2} \cos(\omega t)$ is applied. If the amplification factor $\mu = 14$ and the plate resistance $r_p = 10\,k\Omega$,then the root mean square $(RMS)$ current flowing through the load resistance $R_L = 12\,k\Omega$ will be.......$mA$.