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(C) The amplification factor $\mu$ is defined as the ratio of the change in plate potential to the change in grid potential for a constant plate curre

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$25$

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(C) The amplification factor $\mu$ is defined as the ratio of the change in plate potential to the change in grid potential for a constant plate current.$\mu = -\left( \frac{\Delta V_p}{\Delta V_g} ight)_{I_p = 	ext{constant}}$Given:Initial plate potential $V_{p1} = 200 \ V$,Final plate potential $V_{p2} = 220 \ V$.Change in plate potential $\Delta V_p = V_{p2} - V_{p1} = 220 - 200 = 20 \ V$.Initial grid potential $V_{g1} = -0.5 \ V$,Final grid potential $V_{g2} = -1.3 \ V$.Change in grid potential $\Delta V_g = V_{g2} - V_{g1} = -1.3 - (-0.5) = -0.8 \ V$.Since the plate current remains constant,the amplification factor is:$\mu = -\frac{20}{-0.8} = \frac{20}{0.8} = 25$.

In the circuit of a triode valve,there is no change in the plate current when the plate potential is increased from $200 \ V$ to $220 \ V$ and the grid potential is decreased from $-0.5 \ V$ to $-1.3 \ V$. The amplification factor of this valve is

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