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(D) The dynamic plate resistance $(r_p)$ is defined as the ratio of the change in plate voltage $(\Delta V_p)$ to the change in plate current $(\Delta

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$11.1$

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(D) The dynamic plate resistance $(r_p)$ is defined as the ratio of the change in plate voltage $(\Delta V_p)$ to the change in plate current $(\Delta i_p)$.Given:$\Delta V_p = 150 \, V - 100 \, V = 50 \, V$$\Delta i_p = 12 \, mA - 7.5 \, mA = 4.5 \, mA = 4.5 	imes 10^{-3} \, A$Using the formula:$r_p = \frac{\Delta V_p}{\Delta i_p} = \frac{50}{4.5 	imes 10^{-3}} \, \Omega$$r_p = \frac{50}{4.5} 	imes 10^3 \, \Omega$$r_p \approx 11.1 	imes 10^3 \, \Omega = 11.1 \, k\Omega$.

When the plate voltage in a diode valve is increased from $100 \, V$ to $150 \, V$, the plate current increases from $7.5 \, mA$ to $12 \, mA$. The dynamic plate resistance will be.... $k \, \Omega$.

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