The product (A) of the above reaction is: | vedclass

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(B) The reaction is an example of an intramolecular Wurtz reaction.Sodium $(Na)$ acts as a reducing agent,providing electrons $(e^{\ominus})$ to the s

Vedclass · Accepted Answer

Bicyclobutane

Vedclass · Answer

(B) The reaction is an example of an intramolecular Wurtz reaction.Sodium $(Na)$ acts as a reducing agent,providing electrons $(e^{\ominus})$ to the substrate.The mechanism involves the following steps:$1$. An electron $(e^{\ominus})$ attacks the carbon attached to the bromine atom,leading to the departure of the bromide ion $(Br^{\ominus})$ and the formation of a radical.$2$. Another electron $(e^{\ominus})$ attacks the carbon attached to the chlorine atom,leading to the departure of the chloride ion $(Cl^{\ominus})$ and the formation of a second radical.$3$. The two radicals then combine to form a new $C-C$ bond,resulting in the formation of bicyclobutane.Therefore,the correct product $(A)$ is bicyclobutane.

The product $(A)$ of the above reaction is:

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