The product (A) of the above reaction is: | vedclass

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(D) The given reactant is $CH_3O-CH(CO_2H)-CH_2-CH_2-CH=CH-CH_2-CH_3$. Ozonolysis ($O_3$ followed by $(CH_3)_2S$) cleaves the $C=C$ double bond to for

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$CH_3O-CH(CO_2H)-CH_2-CH_2-CH_2-CHO$

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(D) The given reactant is $CH_3O-CH(CO_2H)-CH_2-CH_2-CH=CH-CH_2-CH_3$. Ozonolysis ($O_3$ followed by $(CH_3)_2S$) cleaves the $C=C$ double bond to form two carbonyl compounds. The cleavage results in: $CH_3O-CH(CO_2H)-CH_2-CH_2-CHO \ (A)$ and $CH_3-CH_2-CHO \ (B)$. Compound $(A)$ is optically active due to the chiral center at the carbon atom attached to the $-OCH_3$ and $-CO_2H$ groups. Therefore,the correct option is $(D)$.

The product $(A)$ of the above reaction is:

Similar Questions

The reaction of trans-but$-2-$ene with $Br_2$ in $CCl_4$ yields products. The number of stereoisomeric products $(X)$ formed is:

What are the $IUPAC$ nomenclature rules for naming alkenes?

Which is the suitable reagent for the above reaction?

Consider the following reaction sequence:
$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$
The major end product formed is:

Product $(A)$ is:
(cyclobutylidene)methylcyclopropane + $HBr \rightarrow A$ (Major)

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