The product (A) of the reaction is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of the given tertiary alcohol with $SOCl_2$ in the presence of pyridine typically proceeds via a carbocation intermediate due to the

Vedclass · Accepted Answer

Vedclass · Answer

(B) The reaction of the given tertiary alcohol with $SOCl_2$ in the presence of pyridine typically proceeds via a carbocation intermediate due to the steric hindrance and the potential for rearrangement. $1$. The hydroxyl group is converted into a good leaving group (chlorosulfite ester),which then departs to form a carbocation. $2$. The carbocation undergoes a ring expansion (Wagner-Meerwein rearrangement) to relieve ring strain and form a more stable carbocation. $3$. Pyridine,acting as a base,then abstracts a proton from the adjacent carbon to form an alkene as the major product. $4$. Based on the provided reaction mechanism image,the final product $(A)$ is the alkene shown in option $(B)$.

The product $(A)$ of the reaction is:

Similar Questions

The major product in the given reaction is

$A$ compound $A$ on oxidation gives acetaldehyde,and further oxidation gives an acid. After the first oxidation,the product reacts with ammoniacal $AgNO_3$ to produce a silver mirror. Compound $A$ is likely to be:

$A \xrightarrow{KOBr} CHBr_3$
Here $A$ is:

The product formed in the following multistep reaction is:

When alcohol vapor is passed over heated reduced copper,the alcohol is converted into an alkene. Which type of alcohol is it?

Vedclass Test Series

Exam Paper Generator

Online Exam Module