The major product in the given reaction is

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(C) The reaction proceeds through the following steps:$1$. Protonation of the hydroxyl group by $H^+$ followed by the loss of a water molecule to form

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(C) The reaction proceeds through the following steps:$1$. Protonation of the hydroxyl group by $H^+$ followed by the loss of a water molecule to form a tertiary carbocation.$2$. The double bond in the chain attacks the carbocation,leading to a cyclization reaction to form a more stable five-membered ring carbocation.$3$. The bromide ion $(Br^-)$ then attacks the carbocation to form the final product.$4$. The structure corresponding to this mechanism is option $C$.

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