The reaction is given as:(CH_3)_2C=C(CH_3)_2 | vedclass

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(B) The reaction of an alkene with $OsO_4$ in the presence of an amine oxide (like $TMAO$) is a catalytic dihydroxylation reaction.$OsO_4$ acts as a c

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$CH_3-C(CH_3)(OH)-C(CH_3)(OH)-CH_3$

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(B) The reaction of an alkene with $OsO_4$ in the presence of an amine oxide (like $TMAO$) is a catalytic dihydroxylation reaction.$OsO_4$ acts as a catalyst to convert the alkene into a vicinal diol (syn-dihydroxylation).The amine oxide acts as the terminal oxidant to re-oxidize the reduced $Os$ species back to $OsO_4$.Therefore,$2$,$3$-dimethyl$-2-$butene reacts to form $2,3-$dimethylbutane$-2,3-$diol.The product $(A)$ is $CH_3-C(CH_3)(OH)-C(CH_3)(OH)-CH_3$.

The reaction is given as:
$(CH_3)_2C=C(CH_3)_2 + (CH_3)_3N^{+}-O^{-} + H_2O \xrightarrow{OsO_4 (10^{-4} \text{ mole})} A + (CH_3)_3N$
Product $(A)$ is:

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The reaction is given as:$(CH_3)_2C=C(CH_3)_2 + (CH_3)_3N^{+}-O^{-} + H_2O \xrightarrow{OsO_4 (10^{-4} \text{ mole})} A + (CH_3)_3N$Product $(A)$ is: