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Question

(D) $1$. The reaction starts with methylcyclopentane reacting with $Br_2/h
u$ (free radical substitution). The major product $(X)$ is $1-$bromo$-1-$m

Vedclass · Accepted Answer

$1-$bromo$-2-$methylcyclopentane

Vedclass · Answer

(D) $1$. The reaction starts with methylcyclopentane reacting with $Br_2/h
u$ (free radical substitution). The major product $(X)$ is $1-$bromo$-1-$methylcyclopentane.$2$. Treatment of $(X)$ with alcoholic $KOH/\Delta$ (dehydrohalogenation) follows $E2$ mechanism to form the more stable alkene,$1$-methylcyclopent$-1-$ene,as the major product $(Y)$.$3$. The reaction of $(Y)$ with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition mechanism. The $Br$ atom attaches to the less substituted carbon of the double bond,resulting in $1-$bromo$-2-$methylcyclopentane as the major product $(Z)$.

The product $(Z)$ is:

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