The products A and B formed in the following | vedclass

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(C) The reaction of $1	ext{-methylcyclohexene}$ with $H^+/H_2O$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule. The carboca

Vedclass · Accepted Answer

$A = 	ext{1-methylcyclohexanol}$,$B = 	ext{2-methylcyclohexanol}$

Vedclass · Answer

(C) The reaction of $1	ext{-methylcyclohexene}$ with $H^+/H_2O$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule. The carbocation formed is more stable at the tertiary position,leading to the formation of $1	ext{-methylcyclohexanol}$ as product $A$.The reaction of $1	ext{-methylcyclohexene}$ with $B_2H_6$ followed by $H_2O_2/NaOH$ is a hydroboration-oxidation reaction,which is an anti-Markovnikov addition of water across the double bond. This leads to the formation of $2	ext{-methylcyclohexanol}$ as product $B$.

The products $A$ and $B$ formed in the following set of reactions are:

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