Product (A) and (B) respectively are :- | vedclass

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(C) The reaction of phenol with $CO_2$ in the presence of $NaOH$ followed by acidification is the Kolbe-Schmidt reaction,which produces salicylic acid

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(C) The reaction of phenol with $CO_2$ in the presence of $NaOH$ followed by acidification is the Kolbe-Schmidt reaction,which produces salicylic acid as product $(A)$.Salicylic acid then undergoes acetylation with acetic anhydride to form aspirin (acetylsalicylic acid) as product $(B)$.In this reaction,the phenolic $-OH$ group is acetylated to form an ester linkage,resulting in $2$-acetoxybenzoic acid.

Product $(A)$ and $(B)$ respectively are :-

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